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Mathematics 7 Online
OpenStudy (ghosting):

The numbers 1 - 9 are written on cards and placed in a bag. Find the probability of choosing a multiple of 3 or an even number. Enter your answer in simplified fraction form; example: 3/5.

zepdrix (zepdrix):

So we're going to count up the possibilities, and then write that number OVER 9, right? Cause we have a total of 9 possibilities.

zepdrix (zepdrix):

multiples of 3 include: 3, 6, 9, 12, 15, 18, 21, ... So which of these numbers do we care about?

OpenStudy (ghosting):

All of them, because they're looking for multiples of 3? @zepdrix

OpenStudy (ghosting):

i dont get it

OpenStudy (anonymous):

1 2 3 4 5 6 7 8 9 Even: 2 4 6 8 Multiples of 3: 3 6 9 So target numbers are: 2 3 4 6 8 9 There are 6 target numbers out of 9 total numbers.

OpenStudy (anonymous):

Assuming every number has an equiprobable change of being selected, we have: \[ \Pr(\text{even or multiple of 3}) = \frac 69=\frac 23 \]

OpenStudy (ghosting):

wait is 2/3 it? i just feel kinda dumb and don't know what's going on witht his question

OpenStudy (anonymous):

There are only 9 numbers, you count how many are even or divisible by 3. The number which meet this condition divided by the total number will give you the probability of meeting the condition.

OpenStudy (ghosting):

.... I am so sorry @wio But I am confused D: !! Okay only 9 numbers... then there are 6 numbers... are 3 are even, 3 divisible by 3. the last part I don't get...

OpenStudy (ghosting):

wait so.... 3.... divided by 9? is 3

OpenStudy (ghosting):

Unsure what my final answer would be...

OpenStudy (ghosting):

@wio

OpenStudy (ghosting):

@AloneS. @AloneS

OpenStudy (anonymous):

The answer is 2/3

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