Question

Help!!!!!!!

Answer 1

Questions here.

Answer 2

recall your SOH CAH TOA
\(sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\)

which identity includes ONLY
the angle
the hypotenuse
and the adjacent?

notice, we're given the adjacent, and the angle, we'll need the hypotenuse

Answer 3

if you haven't covered the trigonometric identities yet, then this exercise doesn't apply to you
or, this will be a good time to cover them firstly

Answer 4

ok

Answer 5

well... assuming you have covered them
notice the cosine function
includes
the angle
the adjacent
and
the hypotenuse
so.... \(\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\implies hypotenuse=\cfrac{adjacent}{cos(\theta)}
\\ \quad \\
c=\cfrac{3}{cos(25^o)}\)

Answer 6

3? what the ?

Answer 7

\(\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\implies hypotenuse=\cfrac{adjacent}{cos(\theta)}
\\ \quad \\
c=\cfrac{8}{cos(25^o)}\)

Answer 8

adjacent??

Answer 9

yes, the adjacent side, is the side touching the angle, usually the shorter one
the opposite is the one facing off the angle
the hypotenuse is the longest side

Answer 10

Yeah.

Answer 11

tan 25 degrees = b / 8

b = 8 * (tan 25 degrees)

@TylerMckinney16

What is the tangent of 25 degrees equal?

Go here to calculate it: http://web2.0calc.com/

Answer 12

Enter what you see and click on "=" to get tangent of 25 degrees

Post what you get, okay?

Answer 13

Whoops. We are looking for c.

So, cosine, not tangent is the function of choice.

cos(25 degrees) = 8/c

c = 8*(cos 25 degrees)

c = ? @TylerMckinney16

Answer 14

Whoops #2

cos (25) = 8/c

c* (cos 25) = 8

c = 8 divided by (cos 25)

c =

Answer 15

@TylerMckinney16 : would you verify that you're taking trig?

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