Question

The limiting line in balmer series will have a frequency of ??
(Rydberg constant ,
R=3.29*10^15 cycle/s)

Answer 1

The value of R is for infinity

Answer 2

@parthkohli

Answer 3

tumne jo information di h voh galat h

Answer 4

\[\large \bf R_{\infty}=1.09 \times 10^7\]

Answer 5

and the value of R you provided is

\[\large \bf R_{\infty} \times c=3.29 \times 10^{15}\]

Answer 6

hope you now solve it :)

Answer 7

I m getting ans having order of 10^39...
Bt there is no option as that

Answer 8

N even i provided you the correct info bcoz the unit of R that i gave is cycles/s..
N u r giving the constant in terms of per metre

Answer 9

Options are
3.65*10^14
8.22*10^14
3.29*10^15
5.26*10^13

Answer 10

its option B (since R/4)..

Answer 11

We are asked about frequency ..the formula for energy is hnu =R /4

Answer 12

no here they have given in cycles/sec

Answer 13

So ??

Answer 14

"frequency is the no. of cycles per unit time"

Answer 15

so we directly use R/4..ok?

Answer 16

Bt the question has not given the units in term of cycle /s
Ans is in units of per s

Answer 17

@priyar

Answer 18

both units are correct!

Answer 19

I think they have given it wrong how can the unit of rydbergy constant be in cycle/s ..evn if we consider mayank's post the unut would be /s

Answer 20

Rydberg*

Answer 21

wait..i will post a bit of info. from a website..

Answer 22

Alright!!

Answer 23

"The SI unit of frequency is the hertz (Hz), named after the German physicist Heinrich Hertz; one hertz means that an event repeats once per second. A previous name for this unit was cycles per second (cps). The SI unit for period is the second."

Answer 24

Now okay?

Answer 25

I think so...

Answer 26

simply apply the formula :-
\[\large \bf frequency=3.29 \times 10^{15}(\frac{1}{2^2}-\frac{1}{\infty^2})\]

Answer 27

you'll get your answer :)

Answer 28

i don't find any difficulty in this question !

Answer 29

I got it already @mayankdevnani

Answer 30

great !