Question

http://prntscr.com/a8z79h
I got -1. Can someone confirm if this was correct?

Answer 1

-1 doesn't seems correct

Answer 2

what is the equation you were solving?

8x/(10x-2) = (5x+3)/7x
or something like that?

Answer 3

You can also solve it using Pythagoras theorem

Answer 4

@FaiqRaees @hartnn
Nope, it's setup as 8x/5x+3=10-2/7x
We haven't learned that yet. We're currently learning how to solve x with proportions.

Answer 5

So, what did I do incorrectly?

Answer 6

so we both have same setup :)

let us know some more steps ? maybe some small algebraic error

Answer 7

Yeah there should be an algebraic error

Answer 8

\(8x \times 7x = (5x+3)(10x-2)\)

Answer 9

So, after 56x I'm having a hard time solving from there. I don't know how to multiple 5x+3 and 10-2 correctly.

Answer 10

you mean 56x^2 ?

Answer 11

No, I cross multiplied. So, I setup mine as 8x/5x+3=10-2/7x and then I cross multiplied to get 56x on one side which is the correct part. It's the other part that I messed up. If you're confused I'll show you a picture.

Answer 12

\(8x \times 7x = (8\times 7) (x\times x) = 56x^2\)

Answer 13

cross-multiplied 8x and 7x, right?

thats comes out to be 56x^2

Answer 14

Why did it come out to the power?

Answer 15

there are 2 x's multiplied,
x*x = x^2

Answer 16

Ah I see. Alright, so, from there, we have to cross multiple 5x+3 and 10-2.

Answer 17

10x-2**
yes

Answer 18

Wouldn't that be 50x^2-6?

Answer 19

there will be 4 terms!
\((a+b)(c+d) = ac+ac+bc+bd\)

Answer 20

Woah, I'm super confused now haha.

Answer 21

\((a+b)(c+d) = ac+ad+bc+bd\)
**

Answer 22

\((5x+3)(10x-2) = 5x \times 10x - 5x\times 2 + 3\times 10x-3\times 2\)

see if this makes sense :)

Answer 23

Definitely doesn't haha.