Solve this word problem. During the summer you want to earn at least $150 per week. You earn $10 per hour working for a farmer, and you can earn $5 per hour babysitting for your neighbor. You can work at most 25 hours a week. A: Write and solve a system of linear inequalities that models the situation. Let x be the number of hours per week working on the farm and let y be the number of hours per week babysitting. After that it needs to be graphed.
@zepdrix
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Answer ^^
\(\large\rm x\) is hours farmed, \(\large\rm y\) is hours babysitting. Total hours must be `less than or equal to 25`.
Is this it? \[x + y \le 25\]
good good good c: sorry a little distracted at the moment
Is that I i have to do ? use that to find out the max number of hours I could work? it sounded like I need more than that.
I have to earn $150 a week but I can't work more than 25 hours
We need to create another equation.
$10 per farm hour, $5 per babysitting hour.
So the total amount of money made farming is \(\large\rm 10x\). That's the rate $10 per hour, times the number of hours farming x.
So likewise, the total amount of money made babysitting is \(\large\rm 5y\)
We need these totals to add up to `at least` 150.
\[x + y \le 25\] \[10x + 5y \ge 150\]
are those right?
Ok great \c:/ So there is our system of equations.
Then we need to graph this information, ya?
yep now we just have to find the largest number possible that fit both right?
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or we go straight to the graph???
Ya let's just graph :3
ok. you know what you're doing. I don't. Just going to trust you here.
\(\large\rm x+y\le25\) Let's get a couple points graphed. First think about it like this: \(\large\rm x+y=25\) If we plug in x=0, \(\large\rm 0+y=25\) Then y=25 solves the equation. This gives us a point, (0,25).
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