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Mathematics 8 Online
OpenStudy (truwhovian11):

MEDAL FOR FIRST ANSWER FAN IF CORRECT Directions: Select all the correct answers. Coach Right is looking at his students' running times in order to place students into running groups. He is working on forming a group that matches Jim's pace of 4 miles in 38 minutes. Which of these student times would fit into a group that runs at the exact same rate as Jim? Zynep ran 3 miles in 27 minutes. Jose ran 5 miles in 45.5 minutes. Prax ran 6 miles in 57 minutes. Sandy ran 7 miles in 66.5 minutes.

OpenStudy (truwhovian11):

@Tennis5518 @MissSmartiez @ShootingStar28

OpenStudy (glitterychan):

Simply divide the number of minutes by the number of miles and it will give you at what speed he ran one mile. Then, do the same for the other four and check which one is the same as Jim.

OpenStudy (truwhovian11):

ummmmmmm WHAT *~*

OpenStudy (truwhovian11):

@Awolflover1

OpenStudy (glitterychan):

Jim's pace: Divide 38 by 4 to get the speed he will run ONE mile in.

OpenStudy (glitterychan):

For example, 38/4 will give us 9.5 . :))

OpenStudy (truwhovian11):

um ok

OpenStudy (truwhovian11):

still dont get it its all just a bunch of numbers to me srry @~@

OpenStudy (truwhovian11):

crap my session timed out sry ill still medal u tho

OpenStudy (glitterychan):

If we divide minutes by the miles they ran we get this: Zynep: 9 Jose: 9.1 Prax: 9.5 Sandy: 9.5 Which of these could fit into a group that runs at the same speed as Jim?

OpenStudy (glitterychan):

im terrible at explaining i apologize sffsdfsfsdf

OpenStudy (truwhovian11):

ok ill still medal and fan tho

OpenStudy (glitterychan):

basically the ones that would fit into a group with Jim were Prax and Sandy

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