Question

NEED help!!!!!

Answer 1

Questions here

Answer 2

@Directrix

Answer 3

Solve the following equation for b.\[\frac{b}{\sin (32 {}^{\circ})}=\frac{5.7}{\sin (180 {}^{\circ}-(69 {}^{\circ}+32 {}^{\circ}))} \]b = 3.07707

Answer 4

Is it 3.08?

Answer 5

do you understand the steps needed to get to @robtobey's equation?

First:
find the value of angle C using the fact that 3 angles in a triangle sum to 180 deg

Second:
Use the sin rule to find side b:

5.7/sin C = b/sin 32

Answer 6

ok what next?

Answer 7

First:
find the value of angle C using the fact that 3 angles in a triangle sum to 180 deg

Answer 8

So - I've helped you with 'what's next' - are you going to work out the value of angle C?

Answer 9

I wanna say its C=79?

Answer 10

69+32+79=180.

Answer 11

@MrNood

Answer 12

yes 79 is correct


so

Second:
Use the sin rule to find side b:

5.7/sin 79 = b/sin 32

sin 79 and sin 32 are just numbers - so you can work out b form there...

Answer 13

Whats the sin rule mean again?

Answer 14

@MrNood

Answer 15

5.7/sin 79 = b/sin 32

Answer 16

sin rule is
a/sin A = b/ sin B = c/ sin C

or in this question

5.7/sin 79 = b/sin 32 (= c/sin 69)

so in this equation you know all except b
5.7/sin 79 = b/sin 32

so you can work out b