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Algebra 15 Online
OpenStudy (anonymous):

A battery has an average life span of 50 hours, with a standard deviation of 3 hours. The life span of the batteries is normally distributed. What percent of the batteries last at least 44 hours?

OpenStudy (mrnood):

how many standard deviations below the mean is 44hours (mean is 50?)

OpenStudy (mathmale):

Mr. Nood's question is appropriate. Stated just a lilttle differently: Find the z-score corresonding to a battery life of 44 hours, given that the mean is 50 and the std. dev. is 3.

OpenStudy (mathmale):

Hint: because 44 is below the mean, the z score in question will be negative.

OpenStudy (mrnood):

then use 68–95–99.7 rule to work out what proportion last LESS than 44 hours the rest last MORE than 44 hours

OpenStudy (mathmale):

@ciaradrake: would you please type in the formula for "z-score."

OpenStudy (mathmale):

Alternatively, using the "68-95-99.7 rule" would enable you to bypass the z-score business entirely.

OpenStudy (mrnood):

gone offline I think!

OpenStudy (mathmale):

;(

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