Please Help Me!!
The equation of a given circle in general form is x2+ y2 − 8x + 12y + 27 = 0. Write the equation in standard form,
(x − h)2 + (y - k)2 = r2, by completing the squares in the equation.
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
first step to make it easier is to write \[x^2-8x+y^2+12y=-27\]
OpenStudy (misty1212):
what is half of 8?
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
4
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OpenStudy (misty1212):
ok so we go right to \[(x-4)^2+y^2+12y=-24+4^2\] that takes care of the \(x\) term
now what is half of 12?
OpenStudy (anonymous):
6
OpenStudy (mathmale):
Cassandra: Just so that you know, the correct approach is "completing the square." You'll need to know this method by name in the future.
OpenStudy (misty1212):
good, so repeating with the y term we get
\[(x-4)^2+(y+6)^2=-27+4^2+6^6\]
of course you still have to compute the right hand side of the equal sign
this is how you complete the square
OpenStudy (anonymous):
okay thank you very much
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