Please Help Me!! The equation of a given circle in general form is x2+ y2 − 8x + 12y + 27 = 0. Write the equation in standard form, (x − h)2 + (y - k)2 = r2, by completing the squares in the equation.
HI!!
first step to make it easier is to write \[x^2-8x+y^2+12y=-27\]
what is half of 8?
okay
4
ok so we go right to \[(x-4)^2+y^2+12y=-24+4^2\] that takes care of the \(x\) term now what is half of 12?
6
Cassandra: Just so that you know, the correct approach is "completing the square." You'll need to know this method by name in the future.
good, so repeating with the y term we get \[(x-4)^2+(y+6)^2=-27+4^2+6^6\] of course you still have to compute the right hand side of the equal sign this is how you complete the square
okay thank you very much
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