Question

What is the equation, in vertex form, of the quadratic function that has a vertex at V(−5, −4) and passes through point P(1, 8)?

Answer 1

the general vertex form is

a(x - b^2 + c

where the vertex is at (b,c) and the value of a can be found if you know one point on the curve

Answer 2

a(x - b^2 + c = 0

Answer 3

a(x-(-5)^2+(-4)=0

Answer 4

so here b = -5 and c = -4
so we can write

a(x - (-5)) + (-4) = 0

Answer 5

right which simoplifies to
a(x + 5)^2 - 4 = 0

now plug in the point (1,8) and solve for a and you have the answer

Answer 6

I should have written it as
y = a(x + 5)^2 - 4

so plug in y = 8 and x = 1

( I'm not at my best today!)

Answer 7

8 = a(1+ 5)^2 - 4
solve for a

Answer 8

Ok let me write this down and I will let you know what I get :)

Answer 9

4

Answer 10

y equals start fraction one over three end fraction left parenthesis x plus five right parenthesis squared minus four

y = 3(x + 5)2 − 8

y equals start fraction negative one over three end fraction left parenthesis x plus five right parenthesis squared plus four

y equals start fraction one over three end fraction left parenthesis x minus five right parenthesis squared minus four

Answer 11

These are my choices though:/

Answer 12

No

6^2 *a = 12
a = 12/36 = 1/3

Answer 13

ohh

Answer 14

So it cant be B or C

Answer 15

so its y = (1/3)(x + 5)^2 - 4

Answer 16

right

Answer 17

which one is it A or D?

Answer 18

Thank you so much! I have one more question, Do you think you can help me out?? And it would be A

Answer 19

A is correct
Please re post another question.