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OpenStudy (mtalhahassan2):
A ball that is thrown up in the air reaches its maximum height. What would its acceleration be at its maximum height?
Question 7 options:
1) 9.8 m/s² [down]
2) 9.8 m/s² [up]
3) < 9.8 m/s² in magnitude
4) > 9.8 m/s² in magnitude
5) 0 m/s²
OpenStudy (mtalhahassan2):
@zepdrix
OpenStudy (mtalhahassan2):
@mathstudent55 @mathmale
OpenStudy (isaidavila):
0 because at the maximum heightthe velocity is 0
OpenStudy (isaidavila):
But it is 9.8 down
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OpenStudy (mtalhahassan2):
so it be 9.8 down right
OpenStudy (mtalhahassan2):
@isaidavila
OpenStudy (mtalhahassan2):
A truck is driving along the highway behind a tractor when it pulls out to pass. If the truck's acceleration is uniform at 2.0 m/s² for 4.0 s and it reaches a speed of 28 m/s, what was its speed when it first pulled out to pass the tractor?
Question 4 options:
1) 24 m/s
2) 20 m/s
3) 18 m/s
4) 22 m/s
5) 26 m/s
OpenStudy (mtalhahassan2):
@NatsuOniKaze @LoveIt @inkyvoyd
OpenStudy (mtalhahassan2):
@Data_LG2
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OpenStudy (mtalhahassan2):
@GracieBugg
OpenStudy (mtalhahassan2):
help me plz
OpenStudy (mtalhahassan2):
@ParthKohli
OpenStudy (michele_laino):
here we can apply this formula:
\[\huge v = {v_0} + at\]
so, we can write:
\[\huge {v_0} = v - at = 28 - \left( {2 \times 4} \right) = ...?\]
OpenStudy (mtalhahassan2):
I get 20
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OpenStudy (mtalhahassan2):
@Michele_Laino
OpenStudy (mtalhahassan2):
The term "uniform motion" means
Question 1 options:
1) acceleration is constant
2) displacement is constant
3) velocity is constant
4) velocity is zero
5) speed is constant
OpenStudy (michele_laino):
that's right! It is \(20\) meters/second
OpenStudy (mtalhahassan2):
is it be 3
OpenStudy (mtalhahassan2):
for # 1
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OpenStudy (michele_laino):
I think it is option #5
Please think about the uniform circular motion, wherein the point has constant speed