Question

Can someone please show me the steps to answer this question?
Find x when 0.02x + 0.7 > 0.8

Answer 1

Subtract 0.7 from both sides then divide both sides by 0.02. :)

Answer 2

could you show me how to do that?

Answer 3

0.02-0.7x + 0.7 > 0.8-0.7
IS this what you meant?

Answer 4

Close...the x has to stay on 0.02

0.02x + 0.7 - 0.7 > 0.8 - 0.7

Answer 5

oh ok

Answer 6

Please share what you currently have.

Answer 7

so then it'll be
0.02x+0.7-0.7>0.8-0.7
=
0.02x+>0.1?

Answer 8

Yes, good!
Now, as a final step, you must solve for x (isolate x).

How would you go about doing that?

Answer 9

wait wait @KamiBug when do i need to divide ?

Answer 10

To isolate x as @mathmale said, you'd divide now that you have 0.02x > 0.1
\[\frac{ 0.02x }{ 0.02 } > \frac{ 0.1 }{ 0.02 }\]

Answer 11

So 0.02x/0.02>0.1/0.02= 1>5?

Answer 12

0.02x+>0.1 should actually be:\[0.02x \ge 0.1\]

Answer 13

Divide each side of this inequality by 0.02. That will give you x alone on the left side.

Please share your work.

Answer 14

wait i'm a little confused

Answer 15

wouldn't it be 1>5?

Answer 16

No. Sorry the stuff I typed earlier didn't come out clearly.\[0.02 \ge0.1\]

Answer 17

is to be divided on both sides by 0.02.

Show your work, please.

Answer 18

so 0.02/0.02=>0.1/0.2?

Answer 19

@KamiBug

Answer 20

Sorry I'm late :o
So right now we have
0.02x > 0.1
Divide bith sides by 0.02 like this
0.02x / 0.02 > 0.1 / 0.02
On the left side, the 0.02 cancles out and you're left only with x.
x > 0.1 / 0.02
Finish simplifying... :)

Answer 21

>5?

Answer 22

thank you very much!! : )