Suppose you drop a ball from a window 32 meters above the ground. The ball bounces to 80% of its previous height with each bounce. What is the total number of meters (rounded to the nearest tenth) the ball travels between the time it is dropped and the 10th bounce?

Question

jskinny0831 · Answer

@surjithayer

jskinny0831 · Answer

i got 253.64 by doing $$s _{10}= 2* 32(1-0.80^10)/1-0.80 -32 $$

jskinny0831 · Answer

A. 110.8 meters
B.  277.1 meters
C.  253.6 meters
D.  221.6 meters

anonymous · Answer

a=32,r=80/100=4/5
10 th bounce means 20 terms
$$s=32*\frac{1- .8^{20} }{ 1-0.8 }$$

jskinny0831 · Answer

is 253.6 correct?

jskinny0831 · Answer

@surjithayer

jskinny0831 · Answer

@mathmale i just wanna know if i did it right, please let me know

jskinny0831 · Answer

@soprano.h.d0816

anonymous · Answer

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i am not clear if it is 19 exponential power or 20 exponential power.

jskinny0831 · Answer

where did you get 19 and 20 from? its asking for the 10th bounce

anonymous · Answer

one coming down and one going up.

jskinny0831 · Answer

ohhhh okay i get it now thank you

anonymous · Answer

i am leaving now.