Question

If sin(theta) = -2/3, which of the following are possible?

Answer 1

i guess lots of things are possible
are you looking for the cosine?

Answer 2

OH! Gomenasai! I forgot to specify...

Answer 3

lol i had to look that up

Answer 4

my japanese is limited to "saki" "samurai" and "unami"

Answer 5

A. \[\sec \theta = -3/2 and \tan \theta = 2/\sqrt{5}\]

Answer 6

slow

Answer 7

don't post any more answers

Answer 8

lets draw a triangle with one side 2 and the hypotenuse 3 like this

Answer 9

there is a picture of an angle whose sine is \(\frac{2}{3}\) as in "opposite over hypotenuse"
don't worry about it being negative yet

Answer 10

what you need is the third side, which you find via pythgoras

Answer 11

Ah, the Pythagorean theorem.

Answer 12

let me know when you get \(a=\sqrt5\)

Answer 13

I'm terrible at this, and I apologize for that.

Answer 14

\[a^2+2^2=3^2\] solve for \(a\)

Answer 15

you can do it in your head
what is 3 squared?

Answer 16

9.

Answer 17

what is 2 squared?

Answer 18

4

Answer 19

And 1 squared, being as it's 1 * itself would be 1, yes?

Answer 20

Wait a minute...

Answer 21

what is 9 - 4?

Answer 22

5

Answer 23

so \[a=\sqrt{3^2-2^2}=\sqrt{9-4}=\sqrt5\] that is all

Answer 24

So A^2=5, ergo A=2.5

Answer 25

ergo my foot
the square root of 5 is not half of 5!

Answer 26

I get it, because the Pythagorean theorem was square values. We have to fin the regular values.

Sorry, demo it is getting really late and I can't think right.