Please Help! Question Attached Below :3 Thank you soo much!
Do you know what you have to do first?
I think so, Im not sure :3
What do you think? :)
hmmm.. maybe we have to OHHH! I know!
\[(4\frac{ 2 }{ 3} + 2 \frac{ 4 }{ 7 }) + 7\frac{ 3 }{ 7 }= \] \[14.6666666667 + 12 = 26.6666666667\]
Am I correct? :3
Where did you get the 12?
It's in the equation :3
\[26.666666666666668 = 80/3 \]
@kayders1997
First you have to add what is in the parenthesis so you have to get a least common denominator
Okay.. hmm..
wow this is hard XD
You could do fractions too though :)
Oh, wait XD I did something wrong!
Omg decimals I didn't get any sleep last night omg!
XD
Hmmm... I really dont know what 14.6666666667 is as a fraction XD
You don't need it in a fraction
Ohh, then what do I put?
Subtract 12 so you can get x all by itself
Do you have a graphing calculator?
Umm, no XD
That's okay so when you subtract 12 you get?
Sorry very irrelevant but how were you able to attach a pic? Because i cant:(
2.6666666667 And tmz, you click the "attach File" button under the chat box :3
Right do you know what that is as a fraction? What is .6666666 as a fraction?
Yes, let me check :3
\[\frac{ 8 }{ 3 }\] thank you! :3
Yes yay! :)
\[\frac{ 8 }{ 3 } = 2\frac{ 2 }{ 3 }\] yayyy!
Overview: 1) Sum up the 3 improper fractions on the left side of this equation, and set this sum equal to the right side: SUM = n + 12 2) Among the ways in which you could sum up the 3 improper fraction on the left side of your equation is that of finding the LCD. Here the LCD happens to be 21, the smallest number that can be divided by both 3 and 7. Example: The first "mixed number" is 4 2/3. Converting this to an improper fraction, 4 2/3 = 14/3. Multiplying numerator and denominator both by the LCD (21), we get \[\frac{ 21*14 }{ 3 }=98\] Treate the 2nd and 3rd improper fractions on the left in the same way.
Omg, thank you mathmale soooo much!!
Keep practicing! I'm happy for your success.
Thank you!!
Join our real-time social learning platform and learn together with your friends!