Question

Can someone please show me the steps to answer this question?
If x = 2 and y = -3, what is the value of 2x^2 - 3xy – 2y^2

Answer 1

Just plug in your X and Y values

Answer 2

so 22^2 - 32-3– 2-3^2

Answer 3

2(2\[2(2^2)-3(2)(-3)-2(-3^2)\]

Answer 4

That should be right

Answer 5

After that just simplify

Answer 6

So
2(2^2) - 3(2)(-3) – 2(2^2)
=
2(4) - 3(2)(-3) – 2(4)

Answer 7

yup

Answer 8

then multiply

Answer 9

2X4-3X-6-8

Answer 10

So
2(2^2) - 3(2)(-3) – 2(2^2)
=
2(4) - 3(2)(-3) – 2(4)
=
2*4=8
3*2=6
6*-3=-18
2*4=8
=

Answer 11

8-18-8?

Answer 12

8--18-8, Don'y forget the negative on the 18 :P

Answer 13

What happens when you have 2 negatives?

Answer 14

positive right?

Answer 15

yes :D so 8+18-8

Answer 16

= 18

Answer 17

You need to be careful when you square a negative number.
\(-3^2 \ne (-3)^2\)

\(-3^2 = -9\)
\((-3)^2 = 9\)

Also, make sure you substitute the correct numbers in for the variables.
\(\color{red}{x = 2}\), and \(\color{green}{y = -3}\).

\( 2\color{red}{x}^2 - 3\color{red}{x}\color{green}{y} – 2\color{green}{y}^2 \)

\(= 2(\color{red}{2})^2 - 3(\color{red}{2})(\color{green}{-3}) - 2(\color{green}{-3})^2\)

\(=2(4) - (-18) - 2(9)\)

\(= 8 + 18 - 18\)

\(= 8\)

Answer 18

The correct answer is 8, not 18.

Answer 19

Do you understand the steps?

Answer 20

Yes sir/ma'am, thank you very very much!!

Answer 21

You're welcome.