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Mathematics 18 Online
OpenStudy (devonhoward15):

what is the turning point of the graph... will fan and medal for correct answer!!f(x)=|x+3|-2 A.(-3,-2) B.(-2,-3) C.(-3,2) D.(2,-3)

OpenStudy (rock_mit182):

Are you asking for the origin of the graph ?

Directrix (directrix):

Go to Desmos.com and graph the equation.

Directrix (directrix):

@Devonhoward15 ^^^

OpenStudy (devonhoward15):

im here

OpenStudy (devonhoward15):

i think (-3,2) is the anwser is that correct?

OpenStudy (rock_mit182):

this function has only one absolute value or maybe there is one more ?

OpenStudy (devonhoward15):

is it -3,2

OpenStudy (devonhoward15):

i graphed it and got -3,-2

OpenStudy (rock_mit182):

yeah that's what we call the origin of the function

Directrix (directrix):

>>>> i graphed it and got (-3,-2) That is what I got.

OpenStudy (devonhoward15):

ok so -3,-2 is the answer?

Directrix (directrix):

Click on the attachment to see the graph.

OpenStudy (rock_mit182):

but look at this: http://www.rasmus.is/uk/t/F/Su53k03.htm

OpenStudy (rock_mit182):

Im not sure why the turning point would be the origin that's where Im confused..

Directrix (directrix):

@rock_mit182 I don't see the connection with the info at that link and the problem under consideration.

OpenStudy (devonhoward15):

got it thank you... i have one more question if you could check if i'm right please

Directrix (directrix):

The origin is (0,0). The turning point here is (-3, -2).

OpenStudy (rock_mit182):

i know what is an origin i just dont know how the two concepst are realated in this case

OpenStudy (devonhoward15):

f(x)=|x-5|+3

OpenStudy (devonhoward15):

4 6 0 11

OpenStudy (devonhoward15):

i got 6

OpenStudy (rock_mit182):

how did you do it ?

OpenStudy (devonhoward15):

|dw:1456879260339:dw|

OpenStudy (rock_mit182):

i see.. but why plug in f of 2 ...

OpenStudy (devonhoward15):

cause it says evaluate f(2)

OpenStudy (rock_mit182):

that's makes a lot of sense !

OpenStudy (rock_mit182):

Lol you didn't post that info..

OpenStudy (devonhoward15):

srry... but am i right?

OpenStudy (rock_mit182):

of course your are

OpenStudy (rock_mit182):

well done

OpenStudy (rock_mit182):

Any other question ?

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