Question

Solving rational equations: Alg II: Will medal best answer

Answer 1

Whats the question?

Answer 2

\[\frac{ 1 }{ 2v }=\frac{ 5v+15 }{ v^2-6v }- \frac{ v+6 }{ 2v^2-12v }\]

Answer 3

...help?

Answer 4

\(\Large \frac{ 1 }{ 2v }=\frac{ 5v+15 }{ v^2-6v }- \frac{ v+6 }{ 2v^2-12v }\)


\(\Large \frac{ 1 }{ 2v }=\frac{ 5v+15 }{ v(v-6) }- \frac{ v+6 }{ 2v(v-6)}\)

multiply by \(v\) allover get this-

\(\Large \frac{ 1 }{ 2 }=\frac{ 5v+15 }{ (v-6) }- \frac{ v+6 }{ 2(v-6)}\)

simplify the left side
find the least common denominator and simplify
you get this-

\(\Large \frac{ 1 }{ 2 }=\frac{ 2(5v+15)-(v+6) }{2( v-6) }\)

\(\Large \frac{ 1 }{ 2 }=\frac{ 10v+30-v-6 }{2( v-6) }\)

\(\Large \frac{ 1 }{ 2 }=\frac{ 9v+24 }{2( v-6) }\)

multiply both sides with \(2(v-6)\) and simplify a bit u get this-

\(v-6=9v+24\)
\(8v=-30\)
\(v=-3.75\)

Answer 5

thank you sooo much!