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Physics 7 Online
OpenStudy (mtalhahassan2):

I need help@@

OpenStudy (mtalhahassan2):

@priyar @Qwertty123 @Ashleyisakitty @escamer @Somy

OpenStudy (mtalhahassan2):

@agent0smith @Astrophysics

OpenStudy (mtalhahassan2):

@Zale101 @ZairaHernandez

OpenStudy (mtalhahassan2):

The direction equivalent to – [40° W of S] is Question 4 options: A) [40° E of S] B) [40° W of N] C) [40° E of N] D) [50° S of W] E) [50° E of N]

OpenStudy (ben00):

I don't understand this.

OpenStudy (mtalhahassan2):

@ParthKohli

OpenStudy (mtalhahassan2):

@ganeshie8

OpenStudy (mtalhahassan2):

@Awolflover1 @batmano3 @Curry @Directrix @haleyelizabeth2017 @inkyvoyd

OpenStudy (mtalhahassan2):

@nincompoop @Kainui @jigglypuff314 @Fifciol @hick4life @rainbowswirl @quickstudent

OpenStudy (mtalhahassan2):

so...are you guys able to help?

OpenStudy (mtalhahassan2):

@KyanTheDoodle

OpenStudy (kyanthedoodle):

http://360investmentadvice.com/wp-content/uploads/2012/12/HiRes.jpg 40 degrees west of south would be the SW right?

OpenStudy (mtalhahassan2):

but how are they getting 50?

OpenStudy (kyanthedoodle):

Because 50 + 40 = 90. And 90 x 4 = 360. 90 is the entire range of a direction, and 40 and 50 are basically the middle part of those directions. Like South West between South and West.

OpenStudy (mtalhahassan2):

oh so its d

OpenStudy (kyanthedoodle):

Exactly.

OpenStudy (mtalhahassan2):

A cyclist cycles 50.0 km [N] and then 30.0 km [E]. The total time taken for the trip is 1.00 h. What is its average velocity? Question 2 options: A) 3.40 × 10 3 km/h [31° E of N] B) 58.3 km/h [31° E of N] C) 3.40 × 10 3 km/h [59° E of N] D) 58.3 km/h [59° E of N] E) 58.3 km/h [NE ]

OpenStudy (mtalhahassan2):

can you please look at this one too

OpenStudy (mtalhahassan2):

thanks for the previous question

OpenStudy (kyanthedoodle):

Sorry but I have no idea for this one. As I said, I'm not good with physics.

OpenStudy (mtalhahassan2):

that's ok

OpenStudy (mtalhahassan2):

@Nnesha

OpenStudy (mtalhahassan2):

@Michele_Laino

OpenStudy (mtalhahassan2):

@jigglypuff314

OpenStudy (fifciol):

|dw:1456912951584:dw| Apply pythagorean to get the velocity vector

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