Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

Steve manages a skate park and he has been analyzing the attendance data. Steve finds that the number of visitors increases exponentially as the temperature increases, and this situation is represented by the function f(x) = 5x. Steve also finds a linear equation that models the number of people who leave the park early depending on the change in temperature, and it is represented by f(x) = −x + 6. The graph of the two functions is below. Find the solution to the two functions and explain what the solution represents.

OpenStudy (anonymous):

OpenStudy (anonymous):

@KyanTheDoodle @just_one_last_goodbye @mathmath333 @Elsa213 @Agl202 @YanaSidlinskiy

OpenStudy (kyanthedoodle):

I have no idea how this works.

OpenStudy (anonymous):

Crud

OpenStudy (anonymous):

@Qwertty123 @samanthagreer @haleyelizabeth2017 @narissa @Keigh2015

OpenStudy (keigh2015):

Algebra?

OpenStudy (anonymous):

Algebra 2

OpenStudy (keigh2015):

Hmm, I don't know, but I can give it a shot.

OpenStudy (anonymous):

Awesome. Thank you.

OpenStudy (narissa):

Temperature is plotted on the x-axis and the number of visitors to the park and the number of visitors who leave the park early is plotted on the y-axis. Solve 5^x = -x+6 5^x + x - 6 = 0 x=1 is a solution by inspection. when x=1, y=5 when the temperature change is 1 degree, the number of people who leave the park early and the number of people who visit the park are equal.

OpenStudy (anonymous):

Yes, but I need a step-by-step way to solve it.

OpenStudy (keigh2015):

Couldn't have said it better myself @narissa

OpenStudy (anonymous):

5^x + x - 6 = 0 is not solvable.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!