Question

What is the equation of a Parabola with the given vertex and focus
vertex (-2,5) Focus (-2,6)
Ayudame!

Answer 1

Hallo?

Answer 2

Hi, have you done any work on this problem yet?

Answer 3

I know it opens upwards, and has an axis of symmetry at -2. Not sure how to find the equation though

Answer 4

(x - h)^2 = 4*a*(y - 5) where (h,k) is the vertex, (-2,5)

(x +2)^2 = 4*a* (y - 5)

Answer 5

Find a

For veretical parabolawhere 'a' is the distance between vertex and focus.

Answer 6

+1 right

Answer 7

a = 1

Answer 8

(y - 5) = (1/4) * (x + 2 )^2

In what form are you instructed to leave the equation?

Answer 9

is the correct equation (x+2)^2+4(y-5) ?

Answer 10

equation of a parabola is all that is says

Answer 11

I'm assuming my answer was right, and the first equation you gave me is correct

Answer 12

(x+2)^2+4(y-5) ?

Where is the equality symbol here.

Answer 13

@Phillip-boot

Answer 14

meant =

Answer 15

But that equation makes sense right?

Answer 16

Hold on while I think.

Will you post the equation you wrote with the = symbol in it.

Answer 17

Click here and look at the graph:

http://www.wolframalpha.com/input/?i=(y+-+5)+%3D+(1%2F4)+*+(x+%2B+2+)%5E2

Answer 18

(x+2)^2=4(y-5)

Answer 19

looks like it's the same graph

Answer 20

Our equations are equivalent.

Same graph, yes.

Vertex and Focus are correct.

Answer 21

Killin it, thanks for checking/evaluating with me mate. You've gained a fan!

Answer 22

You are welcome. You have a new fan, too.