Question

Evaluate the logarithm

simplify log2 2^x

Answer 1

\[\log_{2} 2^{x}\]

Answer 2

as @jdoe0001 said...\[\log_{b}a=x\rightarrow a^{x}=b\]just input the variable values... and solve :-)

Answer 3

i dont understand that

Answer 4

well, same cancellation rule :)

Answer 5

hmmm actually, hold the mayo, is a cancellation rule, just not that one =)

Answer 6

so is the answer just 2x

Answer 7

or x

Answer 8

\(\bf log_{\color{red}{ a}}{\color{red}{ a}}^x\implies x\qquad \qquad thus
\\ \quad \\
log_{\color{red}{ 2}}({\color{red}{ 2}}^x)\implies ?\)

Answer 9

so the answer is x?

Answer 10

yeap

Answer 11

thanks :)

Answer 12

yw

Answer 13

i have another

Answer 14

can u help

Answer 15

use \[\log_{8} 9 \approx 1.057 and \log_{8} 4 \approx 0.667 \]

Answer 16

to evaluate

Answer 17

\[\log_{8 } \frac{ 9 }{ 4 }\]

Answer 18

the equation should be written in this format...\[\frac{\log_{3}9}{\log_{3}4}\]now you have those two values... just put them into this equation and simplify...

Answer 19

where did the 3 come from?

Answer 20

\[\frac{\log_{8}9}{\log_{8}4}\rightarrow\frac{1.057}{0.667}\]sorry, base is 8, screen is very small

Answer 21

i misread... apologies haha

Answer 22

its all good :)

Answer 23

i got 1.58

Answer 24

does it say how many significant figures to round up/down to...?

Answer 25

or is that the full answer... :-o

Answer 26

well 1.585 was the answer choice

Answer 27

i have another thats more difficult like that one i think

Answer 28

yes well... make sure you have the same amount of digits in your answer when rounding, as the answer options...

okay

Answer 29

i think you should make a new post though... this post is very long and laggy lol

Answer 30

use \[\log_{3} 8\approx 1.893 and \log_{3} 5\approx 1.465 \]

Answer 31

to evaluate

Answer 32

\[\log_{3} 40\]

Answer 33

oh... this is one of those equations...
so basically they are saying they got it like this:\[\log_{3}8+\log_{3}5\rightarrow\log_{3}(8\times5)\rightarrow\log_{3}40\]you get it yes?

Answer 34

so they give you values for the 8 and 5... you just need to put in those equations and add them together... \[\log_{3}8+\log{3}5\rightarrow 1.893+1.465=?\]

Answer 35

do you get it?

Answer 36

yes :)

Answer 37

can you help with another

Answer 38

ok good... now here is a set of the log rules so you understand why i am doing it this way... http://www.rapidtables.com/math/algebra/Logarithm.htm

Answer 39

it will help you solve for the rest of the equations with this kind of stuff...
i cannot help you on every single problem, you will not learn :-P

Answer 40

yeah but like they are all different lol

Answer 41

well... if you get the basic rules in the link i sent you... you should be good :-)

Answer 42

here is a really good video link if you are confused on how to apply the formulas... https://www.khanacademy.org/math/algebra2/exponential-and-logarithmic-functions/properties-of-logarithms/v/using-multiple-logarithm-properties-to-simplify :-)

Answer 43

okay thanks

Answer 44

np... good luck ♣