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I believe it is 1200 because all you have to do is read the graph :)
R is the amount of people joining the line, so I need to find the integral from 0 to 5 of the whole graph
But I do not know exactly how to find the integral- do you know how?
no, I don't I' sorry. Good luck!
Since the function is piece wise, you'll need to integrate each part separately.
We will let \(t\) be in hours, and say noon is hour \(0\).
We'll find the number of people to show up by 2 P.M
\(p\) will the function for the number of people at any time.
\[ p(2)-p(0) = \int_0^2 R(t)~dt \]Between noon and 2 P.M. we have \(R(t) = \frac{2100-800}{2-0}t+800\). I used the slope point formula to get this.
Keep in mind they already tell us \(p(0) = 300\).
ah okay so then it would be the integral from 0 to 2 of 650t+800
Whoops, I should have put \(\frac{1200-800}{2-0}\). Do you understand how I got that?
Ah yes using the formula y=mx+b
Okay, so you should be able to get the other \(R\) functions for other intervals.
so then it would be integral of 0 to 2 from 200t+800
and then the next integral would be from 2 to 3 of (1200-800) t + 1200 Am I correct?
no it would be (800-1200)t +1200
integral from 2 to 3 of (-400) t + 1200 right?
The intercept is not going to be \(1200\). before it was a special case that the intercept and initial point were the same.
Wait so how would I go about finding the intercept?
Well, we start with \(y=mx+b\).
We have the equations: \[ y_2=mx_2+b \\ y_1=mx_1+b \]Two linear equations, two variables.
Basically, when you have \(m\), you can use \(y_2-mx_2=b\)
Wait so
When I'm trying to find the equation for 2pm to 3pm
I know the slope is -400
y=-400x + b what x and y values do i plug in
Any point on the line.
and I do need to create two distinct equations? or just one
Well, you have solve for \(m\) the normal way and just use one, I guess
So y=-400x + b, then plugging in a point on the line that i'm trying to find 800=-400(3)+b
\((x,y) = (2,1200)\)
Or \((x,y)=(3,800)\)
so b = -400
no no it would be b=2000
Yes
So this will allow you to solve for \(p(3)\)
then I do, 4, 5, add them all up, and then subtract the number of people who have gotten on the ride, correct?
Yes
We can use the fact\[ p(5) - p(0) = (p(2)-p(0)) + (p(3)-p(2)) + (p(4)-p(3)) + (p(5)-p(4)) \]
I don't understand, I thought I'm just using integrals for each one then adding up each integral
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