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Geometry 14 Online
OpenStudy (tylermckinney16):

Help!!! Fan and medal!!!

OpenStudy (tylermckinney16):

Questions here.

OpenStudy (tylermckinney16):

@nincompoop

OpenStudy (jiteshmeghwal9):

The one which will follow Pythagoras theorem Pythagoras theorem:- \[p^2+b^2=h^2\]here, p= perpendicular, b= base & h= hypotenuse

OpenStudy (tylermckinney16):

Is it A?

OpenStudy (tylermckinney16):

@jiteshmeghwal9

OpenStudy (owlcoffee):

you can check if "A" is the answer by applying the pythagorean theorem: \[4^2 = (\sqrt{10})^2+(\sqrt{7})^2\]

OpenStudy (owlcoffee):

Perform the necessary operations so both sides of the equality are equal.

OpenStudy (tylermckinney16):

I did that and i either think its A or B.

OpenStudy (owlcoffee):

Why not both?

OpenStudy (tylermckinney16):

Cause theres only one answer.

OpenStudy (owlcoffee):

Well, show me how you did it and we'll see more closely which one is not a right triangle. I'll show you an example with "C", by applying the pythagorean theorem we get: \[12^2=(11)^2+(4)^2\] \[144=121+16\] \[144 \ne 137\] Therefore option "c" is not a right triangle.

OpenStudy (tylermckinney16):

ok

Directrix (directrix):

So, what is going on in this thread? Have you arrived at an answer? @TylerMckinney16

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