Try and solve this mathematical riddle if you can, @CheesecakeKitten...
Factor, or thee shalt receive a most wretched tormenting by thyself. x^2 - 8X + 16 These are the four answers that you art to chooseth from. Be not warned, yet there is only one true answer... A. (x + 8)^2 B. (x - 8)^2 C. (x + 4)^2 D. (x - 4)^2
excuse for getting answers for your school? mk
What's that? You'd rather have someone else answer?
I'd rather have someone else birth you, a someone of the lowest caste possible.
hello
=(x2−4x)+(−4x+16) $\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-4x\mathrm{:\quad}x\left(x-4\right)$Factor out x from x2−4x: x(x−4) $\mathrm{Factor\:out\:}-4\mathrm{\:from\:}-4x+16\mathrm{:\quad}-4\left(x-4\right)$Factor out −4 from −4x+16: −4(x−4) $=x\left(x-4\right)-4\left(x-4\right)$=x(x−4)−4(x−4) $\mathrm{Factor\:out\:common\:term\:}\left(x-4\right)$Factor out common term (x−4) $=\left(x-4\right)\left(x-4\right)$=(x−4)(x−4) $\mathrm{Refine}$Refine $=\left(x-4\right)^2$=(x−4)2
The answer to this question is\[(x−4)^2 \]
You receive the medal of honor, dear Sir Jeremiah
You have pleased thy Queen.
;)
I have a few more riddles for you to solve, I know you to be smart-witted, so none shant be quite hard. This here is the second of riddles: Which of these expressions NAY be a perfect square trinomial? A. 144 + 12y + y^2 B. 100 + 20y + y^2 C. 64 - 16y + y^2 D. 25 + 10y + y^2 ((Btw: "Nay be" = "Isn't"))
@retirEEd @Koszakovszky1 needed your help but I help him
i got this
((I'll just post a new question))
okie
@alivejeremy I send you a massage
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