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Mathematics 15 Online
OpenStudy (priyar):

Binomial Q..

OpenStudy (priyar):

\[S _{n} = \sum_{r=0}^{n}\frac{1 }{ \left(\begin{matrix}n \\ r\end{matrix}\right) }\] and \[Tn = \sum_{r=0}^{n}\frac{ r }{ \left(\begin{matrix}n \\ r\end{matrix}\right) }\] then tn/sn =?

OpenStudy (priyar):

@ganeshie8

ganeshie8 (ganeshie8):

.

OpenStudy (priyar):

@freckles

OpenStudy (priyar):

@imqwerty

OpenStudy (priyar):

@samigupta8 can you help?

Parth (parthkohli):

Hi. You can write\[T_n =\sum_{r=0}^{n}\frac{r}{\binom{n}r}=\sum_{r=0}^n \frac{n-r}{\binom{n}{n-r}} = \sum_{r=0}^{n}\frac{n-r}{\binom{n}r}\]So\[T_n + T_n = \sum_{r=0}^n \frac{r}{\binom{n}r} + \sum_{r=0}^n \frac{n-r}{\binom{n}r} = \sum_{r=0}^n \frac{n}{\binom{n}r}=nS_n\]\[\Rightarrow 2T_n = nS_n\]\[\Rightarrow T_n/S_n = n/2\]

OpenStudy (priyar):

wonderful!!

OpenStudy (priyar):

Thanks!

Parth (parthkohli):

No problem. :'(

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