Call the diagonal line y
y^2 = 6^2 + 8^2 ( by Pythagoras theorem)
Now look at the other triangle
Y^2 = 12^2 + x^2 ( by pythagoras again)
Plug the value of y^2 you found iinto the above equation and solve for x^2
x will be the square rootof x^2
OpenStudy (tylermckinney16):
ok im working on it.
OpenStudy (tylermckinney16):
@welshfella i dont understand what to do lol.
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OpenStudy (tylermckinney16):
@SolomonZelman
OpenStudy (welshfella):
can you work out 6^2 + 8^2?
OpenStudy (tylermckinney16):
yeah its 100 right?
OpenStudy (welshfella):
right - so thats the value of y^2
so
12^2 = x^2 + y^2
substituting for y^2 we gat
144 = x^2 + 100
now you need to solve this for x^2
OpenStudy (welshfella):
all you have to do now is subtract 100 from both sides of the equation and you'll get the value of x^2
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OpenStudy (tylermckinney16):
is it 44?
OpenStudy (tylermckinney16):
@welshfella
OpenStudy (welshfella):
yes
so x = squre root of 44
you can get this on ur calculator.
OpenStudy (welshfella):
that will be 6 point something
OpenStudy (tylermckinney16):
so 44 is the answer?
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OpenStudy (tylermckinney16):
@welshfella
OpenStudy (welshfella):
No 44 is not the answer
They want you to find value of x
the answer is the square root of 44
which you can find using your calculator
OpenStudy (welshfella):
your PC's calculator will do it
OpenStudy (welshfella):
gotta go right now..
OpenStudy (tylermckinney16):
6.63324958071 this right?
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