Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

WILL MEDAL AND FAN for best help. A class's exam scores are normally distributed. If the average score is 65 and the standard deviation is 6, what percentage of students scored below 71? Hint: Use the 68-95-99.7 rule. 34% 50% 68% 84%

OpenStudy (kropot72):

The score of 71 is one standard deviation above the average of 65. You can use the diagram to find the solution.

OpenStudy (anonymous):

99.7?

OpenStudy (anonymous):

@kropot72

OpenStudy (kropot72):

Not really. From the diagram, what percentage of the data lies between -1 and 1 standard deviation from the mean?

OpenStudy (anonymous):

68%

OpenStudy (anonymous):

so the center of the graph is the standard deviation of the mean, not the mean its self.

OpenStudy (kropot72):

The point marked zero is the normalized position of the mean. What percentage of the data lies between -1 and -3 standard deviations from the mean.

OpenStudy (anonymous):

oh i already answered that one...... did i misunderstand it?

OpenStudy (kropot72):

50% of the data lies to the left of the mean. 68/2=34% of the data lies between the mean and -1 standard deviation from the mean. Therefore the percentage of the data lying between -1 and -3 standard deviations from the mean is approximately given by 50 - 34 = 16%. |dw:1457028248102:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!