WILL MEDAL AND FAN for best help. A class's exam scores are normally distributed. If the average score is 65 and the standard deviation is 6, what percentage of students scored below 71? Hint: Use the 68-95-99.7 rule. 34% 50% 68% 84%
The score of 71 is one standard deviation above the average of 65. You can use the diagram to find the solution.
99.7?
@kropot72
Not really. From the diagram, what percentage of the data lies between -1 and 1 standard deviation from the mean?
68%
so the center of the graph is the standard deviation of the mean, not the mean its self.
The point marked zero is the normalized position of the mean. What percentage of the data lies between -1 and -3 standard deviations from the mean.
oh i already answered that one...... did i misunderstand it?
50% of the data lies to the left of the mean. 68/2=34% of the data lies between the mean and -1 standard deviation from the mean. Therefore the percentage of the data lying between -1 and -3 standard deviations from the mean is approximately given by 50 - 34 = 16%. |dw:1457028248102:dw|
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