Question

would 7√x*7√x*7√x*7√x be x^4/7 ?

Answer 1

yud

Answer 2

*yes

Answer 3

thanks

Answer 4

\(\bf 7\sqrt{x}\cdot 7\sqrt{x}\cdot 7\sqrt{x}\cdot 7\sqrt{x}?\)

Answer 5

yes

Answer 6

\(\bf 7\sqrt{x}\cdot 7\sqrt{x}\cdot 7\sqrt{x}\cdot 7\sqrt{x}
\\ \quad \\
(7\cdot 7\cdot 7\cdot 7)\cdot (\sqrt{x}\cdot \sqrt{x}\cdot \sqrt{x}\cdot \sqrt{x})
\implies ?\)

Answer 7

\[x^{4/7}\]

Answer 8

hmmm not quite.. is just a straight multiplication pretty much
so, you'd multiply the coefficients by the coefficients and the radicands by the radicands
so \(\bf 7\sqrt{x}\cdot 7\sqrt{x}\cdot 7\sqrt{x}\cdot 7\sqrt{x}
\\ \quad \\
(7\cdot 7\cdot 7\cdot 7)\cdot (\sqrt{x}\cdot \sqrt{x}\cdot \sqrt{x}\cdot \sqrt{x})\implies (7^4)(\sqrt{x^4})\implies ?\)

Answer 9

unless, you meant originally \(\Large \sqrt[7]{x}\cdot \sqrt[7]{x}\cdot \sqrt[7]{x}\cdot \sqrt[7]{x}\)

Answer 10

yeah

Answer 11

thats what I meant

Answer 12

well, hmmm tis, is not the same thing as before :/

Answer 13

sorry

Answer 14

\(\Large {
a^{\frac{{\color{blue} n}}{{\color{red} m}}} \implies \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad

\sqrt[{\color{red} m}]{a^{\color{blue} n}}\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}}\qquad thus
\\ \quad \\ \quad \\

\sqrt[7]{x}\cdot \sqrt[7]{x}\cdot \sqrt[7]{x}\cdot \sqrt[7]{x}\implies \sqrt[{\color{red}{ 7}}]{x^{\color{blue}{ 4}}}\implies x^{\frac{{\color{blue}{ 4}}}{{\color{red}{ 7}}}}
}\)

Answer 15

thank you so much

Answer 16

yw