Hello! Ok so the question is "Predict what kind of solution would be formed when each of the following oxides reacts with water:" one of the oxides are bromine monoxide, how do I write the equation for this, and is there a formula or something I can remember to help me when a question like this comes up again? Thanks!

Question

photon336 · Answer

well it would have to be 

$$Br_{2}O$$ 

Because oxygen needs 2 electrons to complete its octet. and bromine needs 1. so it this must be the formula written above. 

$$Br_{2}O + H_{2}O \rightarrow ~?$$

photon336 · Answer

@Fay-Fay What do you think the product might be?

anonymous · Answer

I believe it could be Br2O + H2O = BrOH ? However I'm not too sure because before I thought it was Br2O + H2O = HBrO + BrO I'm really not sure.. @Photon336

photon336 · Answer

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photon336 · Answer

You notice something right? bromine needs 1 electron to fill its octet while oxygen needs two electrons.  so oxygen makes a bond with bromine and a bond with hydrogen

photon336 · Answer

$$Br_{2}O + H_{2}O \rightarrow ~2BrOH$$

we put the 2 in front of BrOH so that we can balance the equation.

anonymous · Answer

I see :) now, what got me confused is the reaction of nitrogen with water, nitrogen reacting with water creates the equation of 3NO2 + H2O = 2HNO3 + NO why is that equation different from the reaction of water with bromine monoxide?

anonymous · Answer

@phonon336