How do you factor an equation that in brackets has an equation that isn't common? For example: 4c(3d-2)- 3(3d+2) the two equations in brackets are not common so therefore I can not pull them down and create two bracketed equations, so how do I factor this?

Question

phi · Answer

you are correct, you can't factor it.  Maybe it's a typo and the second (3d+2) is really (3d-2) ?
(or the first is (3d+2) )

jdoe0001 · Answer

hmmm hold the mayo

jdoe0001 · Answer

hmmm shoot... missed something.... lemme remove that

jdoe0001 · Answer

the expansion should have been $\bf 4c(3d-2)- 3(3d+2) \implies 12cd-8c-9d-6$

though, either way, no dice on the common factor for the binomials anyway
so... you can't in short :)