For natural numbers m,n if (1-y)^m (1+y)^n = 1+ay+by^2 +..... and a=b= 10, then (m,n) is ?
@Jaynator495 @jigglypuff314 @TheSmartOne @Luigi0210 @robtobey @agent0smith
i got 2 eqs nC1-mC1 = 10 and nC2 +mC2 = 10 ...are these correct?
\(\left[~^mC_0(-y)^0 +~^mC_1(-y)^1+....~^mC_m(-y)^m \right] \left[~^nC_0(y)^0+~^nC_1y^1+...+~^nC_n(y)^n\right]\) you will get the term of format ay only when you multiply something like-> 1 \times y make such cases and then add al cases where ay thing is forming same for by^2
ya i did like this for the first two terms and got the abv.. 2 eqs are they correct?
i am checking the 2nd one 1st one is correct
ok..
@imqwerty?
sorry there was some network error..
oh..its ok
okay the 2nd equation is not correct you can get a y^2 term on multiplying 2 y terms
oh ok...got it!
:)
Thanks!
can you help in the other one also?
Join our real-time social learning platform and learn together with your friends!