Question

help me please.

Answer 1

questions here.

Answer 2

@Directrix

Answer 3

Well, this is a right triangle, so you can apply Pythagoras' Theorem (or, the Pythagorean Theorem as it's more commonly spelt).\[\text{Pythagoras' Theorem}\rightarrow a^{2}+b^{2}=c^{2}\]From what I can see you have b and c, which are 10 and 18, respectively...
So, inputting it into the formulaic equation:\[a^{2}+10^{2}=18^{2}\]Isolating the a would help you get the value for that leg. I'll start you off:\[a^{2}+10^{2}=18^{2}\rightarrow a^{2}+100=324\]\[ a^{2}+100-100=324-100...\rightarrow a^{2}=224...\]So what's a equal? • v •)/

Answer 4

14.97?

Answer 5

14.97???

Answer 6

Well, if they let you give rounded decimals. If not, just keep the square root of 224...\[x=\sqrt{224},\text{ or }x\approx 14.9\]

Answer 7

Actually, the amount of rounding you do on the decimals depends on either the significant figures, the required amount of decimal places, or both :-)

Answer 8

ok

Answer 9

You got it? :-D

Answer 10

yeah lol

Answer 11

Thank so lool.

Answer 12

think

Answer 13

I getcha, no problem ^-^~

Answer 14

To solve the triangle completely means to find the measures of all missing sides and ll missing angles.

So far, you have side AC = √224 = 4√14 or approx 14.967

What about the measures of angles A and B? @TylerMckinney16

Answer 15

Oh right; I forgot about that part... thanks for catching it @Directrix

Answer 16

Right Triangle Trig Refresher Chart.

Answer 17

D:
I was gonna do that...
Lol

Answer 18

Ok so yeah, @TylerMckinney16 which trig function would you like to use for angle ABC?

Answer 19

cos?

Answer 20

Alright :-) do you know where to go from here?

Answer 21

I do some but im not that great at it lol.

Answer 22

Alright well cosine is like this -\[\cos\theta=\frac{adjacent}{hypotenuse}\]Which values are the adjacent (to the angle ABC) leg and hypotenuse, respectively?

Answer 23

The bottom one is the adjacent right?

Answer 24

No, adjacent means "next to" :|

Answer 25

That's the opposite leg, which is used in sine equations... though you could do sine as well since we have all the sides' values

Answer 26

ok cool.

Answer 27

i understand.

Answer 28

Alright, you got it from here? :-)

Answer 29

.-.