Numbers
ok
How many positive integers \(b\) \(\left[\color{orangered}{b <1000} \right] \) are there such that \(\large a^{\lfloor a \rfloor}=b\) has a solution for \(a\).
this is college stuf man
\(\lfloor . \rfloor \) is the floor function
does this help
): sorry but all that is not related to the my question
Let's reverse-solve it. Consider all integers in the interval\[n^n \le \cdots < (n+1)^n\]They'll satisfy your equation for sure. Do \(n = 1\Rightarrow b = 1\) \(n = 2\Rightarrow b \in [4,9)\) \(n=3\Rightarrow b \in [27, 64)\)\[n=4\Rightarrow b \in [256, 625)\]We'll not consider \(n \ge 5\) because \(b \) cannot exceed thousand, and we're gonna be looking at numbers like \(5^5\) which do exceed thousand.
does this help
all these are google searches and this question is not available on google so that won't help
As I highlighted above, the possible solutions for \(b\) are:\[\{1\} \cup [4, 9)\cup [27, 64) \cup [256, 625) \]The number of integers in this interval:\[= 1 + 5 + 37 + 369 = \boxed{412}\]
412
412 is correct! :D
do you wanna read a poem?
@imqwerty
is it 412
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