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A fair coin is tossed 3 times in a row. What is the probability that heads appears on only the last toss?
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@Kitten_is_back
@YoungStudier
#medal given
okay
soooo..... what is the answer?
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holf on
@ajo21
@Error1603
1/8 is the answer
Your right but how did you get it?
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P(2 heads) = 3/8 = 1/4 = 0.375 = 37.5% (HHT, HTH, THH) P(at least 2 heads) = P(2 heads) + P(3 heads) = 3/8 + 1/8 = 4/8 = 0.5 = 50% P(at least 1 head) = P(1H) + P(2H) + P(3H) = 3/8 + 3/8 + 1/8 = 7/8 = 0.875 = 87.5% P(1 head) = 3/8 = 0.375 = 37.5% (HTT, THT, TTH) P(1 head on last toss) = 1/8 = 0.125 = 12.5% (TTH) @klc097
just poped up in m u hwad
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