Prove by mathematical induction for all positive integral values of x, x(x^2+5) is divisible by 6.
the first positive integer is 1 so have you proved it for x=1 yet?
@ganeshie8 @ParthKohli
No I actually am not aware of mathematical induction techniques.
You prove it for the base case. Then you assume it is true for some k within the chosen domain of the problem. Then you show it is true for the case x=k+1.
the base case being x=1 in this case since it is the first positive integer
Can you explain it in a little more detail
I know you want it proven by induction, but here is a quick way to convicne yourself that the given statement is indeed true : \[x(x^2+5)\equiv x(x^2-1) = (x-1)x(x+1)\] Recall that the product of any 3 consecutive integers is divisible by 3 factorial
How is +5 equals to -1
5 = 6 - 1 since 6 is dividible by 6, you can replace it by 0
Perhaps this is more clear : \[x(x^2+5) = x(x^2-1+6) =x(x^2-1) + 6x = (x-1)x(x+1) + 6x \] Again, this has nothing to do with induction...
@ganeshie8 Okay now can you explain it woth induction
You need to know how/why induction works first
Yeah
Let me ask you a question
Consider the set of negative integers. Is there a minimum element in this set ? If a minimum element exists, what is it ?
Yes and I suppose 1, and what's the name of the technique you used above to prove the statement
do you mean, 1 is the minimum element in the set of "positive integers"
Oh they are saying that you have to use positive integral values
and what's the name of the technique you used above to prove the statement
Earlier proof is based on simple divisibility arguments We expressed the given expression as a product of 3 consecutive integers; then we used the fact that product of any 3 consecutive integers is divisible by 3 factorial.
don't pay too much attention to it you want to do this using induction right ?
Yes
Lets get back to induction
sure
Suppose I give you a machine that does this : if you input a positive integer \(k\), the machine spits out the next integer \(k+1\) |dw:1457104609613:dw|
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