Question

help

Answer 1

An electronics company used a pipe that was 100 ft long and had a radius of 10 ft. Inside the pipe was a smaller cylindrical tube, for wires, that had a radius of 2 ft and was as long as the pipe. The remaining space in the pipe, outside the tube, was filled with liquid foam.

What was the volume of the foam inside the pipe? Use 3.14 to approximate pi.


ft3

A diagram showing the outline of a horizontal cylinder with a vertical line stretching from the middle of the cylinder's base to its edge. Next to the line is the label ten feet. Next to the horizontal edge of the cylinder is the label one hundred feet. Inside the cylinder is the dotted outline of a smaller cylinder with a dotted vertical line stretching from the middle of the smaller cylinder's base to its edge. Next to the dotted line is the label two feet.

Answer 2

https://static.k12.com/calms_media/media/1565500_1566000/1565642/1/9144ecf03f73c3e133113fa4772b62b13b1176fe/MS_IMC-1401119-110023.jpg

Answer 3

@alex6799

Answer 4

30144 cubic feet.

Answer 5

Alice purchased paint in a bucket with a radius of 9 in. and a height of 9.5 in. The paint cost $0.09 per in3.

What was the total cost of the paint, rounded to the nearest cent?
Use 3.14 to approximate pi.

Answer 6

So for the ALICE one you would have to find the volume of the bucket....

\(\huge{V= \pi r^{2}h}\) So we input what we know of...

\(\huge\color{green}{V=3.14(9^{2})9.5}\) In which you would simplify...

What would be the volume?

Answer 7

300

Answer 8

Do you mean as the price or volume?

Answer 9

@alex6799 plz do not give direct answers to the openstudier who needs help otherwise they will never get on how to solve the problem....this is in violation of the code of conduct....

Answer 10

The Volume would equal to \(\huge{2416.23~in^{3}}\)

But we would then multiply this by \(\large{$0.09}\)....

\(\huge\color{orange}{2416.23 \times 0.09 = price}\)