Quadrilateral BCDE is inscribed in circle A as shown. BD divides the quadrilateral into two triangles, ΔBCD and ΔBED. Which statement is true about the triangles?
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OpenStudy (anonymous):
The angle bisectors and the perpendicular bisectors for both triangles intersect at the same point.
The angle bisectors of ΔBCD intersect at the same point as those of ΔBED.
The perpendicular bisectors of ΔBCD intersect at the same point as those of ΔBED.
The angle bisectors of ΔBCD intersect at the same point as the perpendicular bisectors of ΔBED.
OpenStudy (anonymous):
@ShadowLegendX @rebeccaxhawaii
OpenStudy (jonathan34):
what is these?
OpenStudy (anonymous):
???
OpenStudy (jonathan34):
what do you need?
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OpenStudy (anonymous):
is the question not clear enough?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
i understood that it wasnt c its the angle bisectors that confuse me
OpenStudy (shadowlegendx):
@rebeccaxhawaii you totes got this c;
rebeccaxhawaii (rebeccaxhawaii):
so the bisector is the BD line
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OpenStudy (anonymous):
the line BD makes the two triangles in question
OpenStudy (jonathan34):
look it is c i think
OpenStudy (anonymous):
we just ruled C out
OpenStudy (jonathan34):
but am not 100% but i think it is c
OpenStudy (jonathan34):
no c is the bd
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OpenStudy (jonathan34):
isnt that what you want?
OpenStudy (jonathan34):
ow i had to reread
OpenStudy (anonymous):
we want the statement that is true for both triangles and neither triangles have perpendicular bisectors
OpenStudy (jonathan34):
ok b is 100% opposite from A they have nothing to do from each other
OpenStudy (jonathan34):
so b is going to be your answer i think
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