Mathematics
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alones (alones):
How would I factor this ._>
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alones (alones):
-3x - 3y - 3z
OpenStudy (kamibug):
What's the same in each term? :)
alones (alones):
3 is same :3
OpenStudy (fortytherapper):
Yes, but there is a minus in front of each 3, so what would the common number really be?
alones (alones):
Oh -3?
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OpenStudy (fortytherapper):
Right, so we can factor that -3 out by diving each term by -3
OpenStudy (kamibug):
And putting the -3 on the outside of parenthesis. ^.^
-3('in here go the other terms after you divided them by -3')
CX
alones (alones):
K so it would look like this ? -3(x-y-z)
OpenStudy (kamibug):
Don't forget you're dividing out the negatives too! A negative divided by a negative becomes a positive
So -3x / -3 = +x
OpenStudy (fortytherapper):
Almost, just one little thing you forgot to do when dividing
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OpenStudy (fortytherapper):
Yes, what Kami said
alones (alones):
Okay i see like this -3(x + y + z)
OpenStudy (kamibug):
Correct. :D
alones (alones):
O.O IT'S CORRECT
alones (alones):
THANK YOU GUYS<3<3
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ILovePuppiesLol (ilovepuppieslol):
no problem
ILovePuppiesLol (ilovepuppieslol):
happy to contribute
OpenStudy (fortytherapper):
Yep, if I distribute that
\[-3(x+y+z)\]
I get
\[-3x -3y-3z\]
ILovePuppiesLol (ilovepuppieslol):
please close this question, thanks e.~