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Geometry 11 Online
OpenStudy (melstutes):

If distance between 2 points is 10, find the ordered pair that is 1/3 of the distance of AB from endpoint A. A (-3, 4 and B (5,-2)

OpenStudy (mathmale):

Try this: Find the horiz. distance from -3 to 5. Take 1/3 of that. Find the vertical distance from 4 to -2. Take 1/3 of that. The results should give you the coordinates of the point that is 1/3 of the length of AB from endpoint A. Consider drawing a picture.

OpenStudy (melstutes):

I don't understand

OpenStudy (melstutes):

I used distance formula to find length and it is 10, then I am lost

OpenStudy (mathmale):

Please respond with questions about whatever it is you don't understand. Have you sketched this situation? If not, why not? Hint: The length, 10, is the hypotenuse of a right triangle. Find the lengths of the legs. You don't need the distance formula to find the length of AB, since you are TOLD that it is 10.

OpenStudy (mathmale):

What is the horiz. distance from A to B? (horiz. ONLY). What is the vert. dist. from A to B? Vert. ONLY.

OpenStudy (melstutes):

I wasn't told that - I had to figure that out this is second part of problem

OpenStudy (mathmale):

(vert dist)^2 + (horiz dist)^2 = 10^2 (Pythagorean Theorem). Finished your sketch yet?

OpenStudy (mathmale):

Hint: This is a 6-8-10 triangle.

OpenStudy (melstutes):

question reads without graphing, find the length of AB

OpenStudy (melstutes):

next part - find the ordered pair that is 1/3 of the distance of AB from endpoint A

OpenStudy (mathmale):

You continue to brush aside my suggestions. I can't be of much help if you won't do anything I ask. You do not need to find the length of AB. It is clearly given, and is 10. I've been willing to guide you thru this problem; I am not willing to do the work for you.

OpenStudy (melstutes):

I am trying to explain that 10 was not given - I was able to do that part independently

OpenStudy (melstutes):

It gave me the coordinates and I found the length

OpenStudy (melstutes):

I am asking for an explanation not for you to do it for me, sir

OpenStudy (mathmale):

It would have helped had you shared the entire problem with me, so I could better see where you're coming from. A and B are given, and yes, the length of AB is 10. That's not the question here. 1. 3 times I've mentioned "sketch" or "draw" this situation. 2. 2 times I've asked you to find the vertical and horiz distances between A and B. Where's the scoop?

OpenStudy (melstutes):

I don't understand how to draw it - sorry

OpenStudy (mathmale):

In essence you must start at A and travel to B. If you know the horiz. distance from A to B, then all you have to do is to take 1/3 of that distance and add it to the x-coordinate of A. Since A is A(-3,4) and B is B(5,-2), the horiz. dist from A to B is 8. You figure out where that came from, please. One third of 8 is 8/3. Add 8/3 to the x-coord of A, which is -2). The combination of those two is repr. the horiz distance of a point that is (1/3) of the dist. from A to B. This is not the only way in which you can solve this problem, but I think it the simplest.

OpenStudy (mathmale):

What is the vert. distance from A to B? What is (1/3) of that?

OpenStudy (melstutes):

6 so 2

OpenStudy (mathmale):

Yes. So, start at point A. A(-3,4). Add 2 to that -3 and you will have the y-coord. of the point which is 1/3 of the distance from A to B. Do we already have the x-coord of that point? Review our discusstion, please.

OpenStudy (melstutes):

.66?????????

OpenStudy (mathmale):

Is -3 + 8/3 equal to .666???

OpenStudy (melstutes):

(5.66, -5)

OpenStudy (mathmale):

I have a visitor coming and need to get off the 'net. Please go back and review this conversation: x coord of that point 1/3 of the way from A to B is -3+8/3 (which is much smaller than 5.66) y coord of that point is 2-3=? The point 1/3 of the way from A to B is (-1/3, ?? ) sorry, I'm getting off, not because of you, but because I have other obligations at the very moment. Thanks for working with me.

OpenStudy (melstutes):

.33

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