Question

I need help ASAP, please!!!!
I am stuck trying to do this integral
integral of (-36x^(2)-69x-22)/(9x^(2)+18x+8) dx
I been trying to do it using partial fractions but I am not getting anywhere T_T

Answer 1

see divide the numerator by the denominator and express the integrand as
\[Q(x) + \frac{ R(x) }{ 9x^2 + 18x + 8 }\]

Answer 2

I am struggling solving for A & B :(

Answer 3

hmmmmm why solve it using partial fractions.....

Answer 4

I end up with 3x+10=A(3x+4)+B(3x+2)

Answer 5

@lili18 see solve it this way....
divide the numerator with the denominator

Answer 6

how do i solve for a and b on the following; 10=2a+4b? please, help!!!

Answer 7

hmmmm u got 1 equation and 2 variables ???

Answer 8

yes that when x=0

Answer 9

to solve these type of question...... go on with the way I mentioned above

Answer 10

see to solve it using partial fractions ....
first step is divide the numerator by the denominator.....
u will get
\[- 4 + \frac{ 3x + 10 }{ 9x^2 + 18x + 8 }\]
now solve using partial fractions :))

Answer 11

so it would be
\[\frac{ 3x + 10 }{ (3x + 2)(3x + 4) } = \frac{ A }{ 3x + 2 } + \frac{ B }{ 3x + 4 }\]

Answer 12

@lili18 can u solve it now???

Answer 13

@lili18 u there??

Answer 14

\[3A +3B = 3 \rightarrow A+B = 1\]
\[4A +2B = 10 \rightarrow 2A +B = 5\]
solve by substitution
\[2A + (1-A) = 5\]
\[A = 4\]
\[B = -3\]