Question

Centroids

Answer 1

@rvc @satellite73 if either of you are free :>

Answer 2

i am free, but i have no idea
how do you find a centroid? i guess we can look it up

Answer 3

maybe they just want you to get rid of that silly compound fraction for the x coordinate

Answer 4

ok here is a picture of the region
http://www.wolframalpha.com/input/?i=8sin%282x%29,+8cos%282x%29+domain+0..pi%2F8

Answer 5

and the area is \(4\sqrt2-4\)

Answer 6

you got that part i guess

Answer 7

is \[M_y=8\int_0^{\frac{\pi}{8}}x\cos(2x)-x\sin(2x)dx\]?

Answer 8

yeah..hm

Answer 9

for xbar I got
\[\frac{ \pi/\sqrt{2} -2}{ 4\sqrt2-4 }\]

Answer 10

ok i didn't get there yet, let me wolfram a sec

Answer 11

yeah got that

Answer 12

maybe clean it up by multiplying top and bottom by \(\sqrt2\)

Answer 13

get \[\frac{\pi-2\sqrt2}{8-4\sqrt2}\]

Answer 14

shall we try for \(\overline{x}\)?

Answer 15

ok! I need to clean up y because I have to enter them together xD

Answer 16

so ybar
(pi-2)/(sqrt2 -1)

Answer 17

i would leave it like that
for \(\overline{x}\) i get 8 for the numerator

Answer 18

oh also i think you have them backwards

Answer 19

x goes first no?

Answer 20

is this your y bar