Question

Help please (this has been driving me crazy)

Answer 1

\[\left| x \right|>\left| x^2-4 \right|\]

I got the values needed for the answer but all the inequality signs are wrong. I can't seem to see the problem witih my answer either

Answer 2

square both sides and then solve

Answer 3

and also \[x+\left| x+5 \right| +\left| x+3 \right|=\frac{ \left| 6x-6 \right| }{ \left| 1-x \right| }\]

Answer 4

but that will leave me with a degree of 4 which is hard to solve

Answer 5

i tried putting it like
-x<x^2-4<x but I'm not sure if its right

Answer 6

@phi (much love)

Answer 7

i think you have put intermidiate of your answer.

Answer 8

i mean solution

Answer 9

please consider the subsequent drawing:

here we have to subdivide the real line i these subsequent sets:
\(x<-2\)
\(-2<x<0\)
\(0<x<2\)
\(x>0\)

Answer 10

for example, if \(x<-2\), then we can rewrite the inequality, as below:
\(-x>x^2-4\)
so, please solve

Answer 11

if \(x=-2\), then the inequality reads:
\(2>0\)
which is true, so \(x=-2\) belongs to the set of solutions

Answer 12

for the first one you could square both sides to get an equation in x^4 which is not too difficult to solve
x^2 = x^4 - 8x^2 + 16
x^4 - 9 x^2 + 16 = 0 the inequality will be x^4 - 9x^2 + 16 < 0

let x^2 = Y and solve for Y using the quadratic formula

there will be 4 zeroes

Drawing the graph using software (like Desmos) will show you what the inequalities are.

Answer 13

or you can use a graphical calculator.
the graph looks somethin like this