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Mathematics 7 Online
OpenStudy (anonymous):

Can someone help me with number 31 in the image below?

OpenStudy (triciaal):

are you getting the image?

OpenStudy (anonymous):

Oops, it showed it attached when i uploaded the question

OpenStudy (anonymous):

Here's the problem

OpenStudy (johnweldon1993):

|dw:1457309133086:dw| Well, we know that the total height is 18ft That 18 ft is now split between the hypotenuse of the triangle and what is left standing

OpenStudy (caozeyuan):

3, 4,5 and 5, 12, 13 should be memorized

OpenStudy (caozeyuan):

now you can just see the right triangle and has one side of 12, and go " oh, I recognize 5, 12, 13 as sides of right triangles!

OpenStudy (caozeyuan):

since 12, is one of the side, and 5+13 is 18, you are be sure you are correct, this is probably the fastest way to do this problem

OpenStudy (johnweldon1993):

^True that is a quick way to do this, Pythagorean triplets are a good thing to have in the back pocket...if you weren't that lucky.it would follow this process: We can say that \(\large x + h = 18\) so solving that for 'x' we find that \(\large x = 18 - h\) So now we just use the Pythagorean identity of \(\large a^2 + b^2 = c^2\) Or in this case \(\large 12^2 + h^2 = (18 - h)^2\) Lets simplify \[\large 144 + h^2 = 324 - 36h + h^2\] Notice \[\large 144 + \cancel{h^2} = 324 - 36h + \cancel{h^2}\] So what we have is \[\large 144 = 324 - 36h\] Or \(\large h = \frac{144 - 324}{-36} = 5\)

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