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Mathematics 14 Online
OpenStudy (k12awesomeness):

The graph shows the distances traveled by two bikers. A third biker travels 24 miles in 3 hours. How does the third biker compare with Biker 1 and Biker 2? A. The third biker is slower than both Biker 1 and Biker 2. B. The third biker is faster than both Biker 1 and Biker 2. C. The third biker is faster than Biker 1 but slower than Biker 2. D. The third biker is faster than Biker 2 but slower than Biker 1. https://static.k12.com/calms_media/media/1418000_1418500/1418066/1/2965dc10b1d2a3e0cc8d9b8ad9046db22703554a/FGA_130919_161155.jpg

OpenStudy (k12awesomeness):

help please

563blackghost (563blackghost):

You could find the unit rate of each biker....first determine a point for the first biker and one for the second biker....

563blackghost (563blackghost):

@K12awesomeness

OpenStudy (k12awesomeness):

okay

OpenStudy (k12awesomeness):

@563blackghost

563blackghost (563blackghost):

So we can use (4,40) for the first biker and (5,45) for the second biker and we know of the point for the third biker which is (3,24)....so in order to find out how many miles they can do in an hour we must divide \(\Large{\frac{y}{x}}\).... \(\Huge{Biker~1=\frac{40}{4}=\frac{miles}{one~hour}}\) \(\Huge{Biker~2=\frac{45}{5}=\frac{miles}{one~hour}}\) \(\Huge{Biker~3=\frac{24}{3}=\frac{miles}{one~hour}}\)

OpenStudy (k12awesomeness):

thx!!

563blackghost (563blackghost):

np :)

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