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Mathematics 15 Online
OpenStudy (kaioken360):

Could someone please help? (Question on image)

OpenStudy (kaioken360):

Directrix (directrix):

If you will solve this equation for x and post the answer, then I will help you complete the problem. 5^2 + 12^2 = x^2 We need x for the slant height of the cone. @kaioken360

563blackghost (563blackghost):

Like @Directrix said we would find the slant height... \(\Huge{5^{2}+12^{2}=c^{2}}\) Simplify... \(\Huge\color{orange}{25+144=c^{2}}\) Add.... \(\Huge\color{green}{169=c^{2}}\) Now we need square root 169... \(\Huge\color{red}{\sqrt{169}=c}\) What is c?

OpenStudy (kaioken360):

338?

563blackghost (563blackghost):

Incorrect....we need to find a number that multiples itself to equal 169 so it can not be bigger then the number....

OpenStudy (jdoe0001):

hint: \(\textit{surface area of a cone}=\pi r\sqrt{r^2+h^2}+\pi r^2\qquad \begin{cases} r=radius\\ h=height \end{cases}\)

OpenStudy (kaioken360):

13

Directrix (directrix):

I had in mind for the OP to find the slant height. Then, use the formula TA = pi * r * L = pi * r^2 where L is the slant height.

Directrix (directrix):

13 is correct for the slant height

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