Question

Find the absolute value
|1-i|

Answer 1

the absolute value of \(a+bi\) is \(\sqrt{a^2+b^2}\)
in your case \(a=1.b=-1\)

Answer 2

I've tried -1, still saying incorrect.

Answer 3

ok first off, the absolute value is always positive, so it can't be -1

Answer 4

what is \(1^2\)?

Answer 5

$$ |1 - i | = \sqrt{ 1 + (-1)^2 } = \sqrt{ 1 + 1 }$$ can you finish it