more Thermodynamics. @Photon336
http://i.imgur.com/Mg5hxlu.png

Question

more Thermodynamics. @Photon336
http://i.imgur.com/Mg5hxlu.png

littleredriding · Answer

@Photon336

photon336 · Answer

So look at the units 


$$16.5~grams~H_{2}O$$

$$H_{v} = 2260 \frac{ J }{ g }$$


all you would need to do is multiply them out: 

Hv*(# of grams)

photon336 · Answer

if you multiply them together you end up getting joules the unit you want.

littleredriding · Answer

Oooh...so is the equation  2260 J/g   the formula and I have to plug in the numbers after converting them to the right units if need be? So do I set it up like : $$2260 \times  \frac{ 1 J}{ 16.5} = 136.97$$

littleredriding · Answer

@Photon336

photon336 · Answer

Let me show you

littleredriding · Answer

Okay. @Photon336

photon336 · Answer

You set it up like this. If you notice grams cancel out exactly as we want and were left with joules.

2260 (j/g) * 136g = joules

littleredriding · Answer

Where did the 136 come from?

littleredriding · Answer

I found it with my other formula...but that was my answer so I'm not exactly sure how you found it....

littleredriding · Answer

@Photon336  is it 37290J?

anonymous · Answer

$$Hv=\frac{ Work }{ Mass }$$ so you simply rearrange for work which is what you want and your're already given the value for Hv and Mass.

littleredriding · Answer

How do I find the work?

anonymous · Answer

You rearrange the equation I wrote above to $$Work=Hv \times Mass=(2260 j/g) \times (16.5 g)$$

littleredriding · Answer

So is the work 37290? @ohernand

anonymous · Answer

Yes, that is the correct answer.

littleredriding · Answer

Yay! Thank you so much!

anonymous · Answer

No problem