more Thermodynamics. @Photon336 http://i.imgur.com/Mg5hxlu.png
@Photon336
So look at the units \[16.5~grams~H_{2}O\] \[H_{v} = 2260 \frac{ J }{ g }\] all you would need to do is multiply them out: Hv*(# of grams)
if you multiply them together you end up getting joules the unit you want.
Oooh...so is the equation 2260 J/g the formula and I have to plug in the numbers after converting them to the right units if need be? So do I set it up like : \[2260 \times \frac{ 1 J}{ 16.5} = 136.97\]
@Photon336
Let me show you
Okay. @Photon336
You set it up like this. If you notice grams cancel out exactly as we want and were left with joules. 2260 (j/g) * 136g = joules
Where did the 136 come from?
I found it with my other formula...but that was my answer so I'm not exactly sure how you found it....
@Photon336 is it 37290J?
\[Hv=\frac{ Work }{ Mass }\] so you simply rearrange for work which is what you want and your're already given the value for Hv and Mass.
How do I find the work?
You rearrange the equation I wrote above to \[Work=Hv \times Mass=(2260 j/g) \times (16.5 g)\]
So is the work 37290? @ohernand
Yes, that is the correct answer.
Yay! Thank you so much!
No problem
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