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Chemistry 7 Online
OpenStudy (littleredriding):

more Thermodynamics. @Photon336 http://i.imgur.com/Mg5hxlu.png

OpenStudy (littleredriding):

@Photon336

OpenStudy (photon336):

So look at the units \[16.5~grams~H_{2}O\] \[H_{v} = 2260 \frac{ J }{ g }\] all you would need to do is multiply them out: Hv*(# of grams)

OpenStudy (photon336):

if you multiply them together you end up getting joules the unit you want.

OpenStudy (littleredriding):

Oooh...so is the equation 2260 J/g the formula and I have to plug in the numbers after converting them to the right units if need be? So do I set it up like : \[2260 \times \frac{ 1 J}{ 16.5} = 136.97\]

OpenStudy (littleredriding):

@Photon336

OpenStudy (photon336):

Let me show you

OpenStudy (littleredriding):

Okay. @Photon336

OpenStudy (photon336):

You set it up like this. If you notice grams cancel out exactly as we want and were left with joules. 2260 (j/g) * 136g = joules

OpenStudy (littleredriding):

Where did the 136 come from?

OpenStudy (littleredriding):

I found it with my other formula...but that was my answer so I'm not exactly sure how you found it....

OpenStudy (littleredriding):

@Photon336 is it 37290J?

OpenStudy (anonymous):

\[Hv=\frac{ Work }{ Mass }\] so you simply rearrange for work which is what you want and your're already given the value for Hv and Mass.

OpenStudy (littleredriding):

How do I find the work?

OpenStudy (anonymous):

You rearrange the equation I wrote above to \[Work=Hv \times Mass=(2260 j/g) \times (16.5 g)\]

OpenStudy (littleredriding):

So is the work 37290? @ohernand

OpenStudy (anonymous):

Yes, that is the correct answer.

OpenStudy (littleredriding):

Yay! Thank you so much!

OpenStudy (anonymous):

No problem

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