The form of the partial fraction decomposition of a rational function is given below.
integral of
5x^2+5x+30/(x−3)(x^2+9)=A/(x−3)+Bx+C(x^2+9)

Question

The form of the partial fraction decomposition of a rational function is given below. 
integral of
5x^2+5x+30/(x−3)(x^2+9)=A/(x−3)+Bx+C(x^2+9)

anonymous · Answer

attachment

anonymous · Answer

assuming your partial fractions are right, and it says they are, then your answer is right

anonymous · Answer

the answer is right but it keeps saying there is more than one way to answer and I am not sure what that would be

anonymous · Answer

My partial fractions are 
(5/((x^2)+9))+5/(x-3)

anonymous · Answer

idk try answering it like this http://www.wolframalpha.com/input/?i=integrate+%285x^2%2B5x%2B30%29%2F%28%28x%E2%88%923%29%28x^2%2B9%29%29

anonymous · Answer

yeah your partial fractions are right

anonymous · Answer

maybe it wants a +C at the end, who knows?

anonymous · Answer

yeah I tired both things

freckles · Answer

I might try to write the answer as 
$$5(\frac{1}{3} \tan^{-1}(\frac{x}{3})+\ln|x-3|)+C$$
notice I put | | around the inside of the natural log thing
and I also put plus a constant

anonymous · Answer

okay that worked, thank you!

anonymous · Answer

I didn't even notice I forgot to add the | |

freckles · Answer

np