Question

I have to do an extraneous equation with the problem I posted below. So far I did that but the teacher said I'm missing something. Can someone help me on what I'm missing to make it an extraneous solution

Answer 1

I think squaring a function may cause an extraneous solution. But you probably want to check with someone else about it.

Answer 2

okay thanks

Answer 3

well you are right on the domain being restricted. because if our denominator is (x)(x+1) x can't be 0 and -1

Answer 4

okay

Answer 5

but I think to get the extraneous solution we have to do something to the numerator ?

Answer 6

An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.

So it's like we need one x that's false for the equation .

Answer 7

What do you mean by a root of a transformed equation?

Answer 8

When you add, subtract, multiply, divide or square both sides of an equation you are transforming it into an equivalent equation.

Answer 9

oh okay

Answer 10

The teacher said I'm just missing something to make it an extraneous equation

Answer 11

I feel like I have to square root something but Im not sure